Sign up ×
Android Enthusiasts Stack Exchange is a question and answer site for enthusiasts and power users of the Android operating system. It's 100% free, no registration required.

Is there a website or even Android app that keeps its subscribers updated of any possible promotions/discounts going on at Google Play (previously Android Market)? I hate to miss the train.

share|improve this question

closed as off-topic by Al E., geffchang, Dan Hulme, eldarerathis Nov 17 '13 at 4:42

This question appears to be off-topic. The users who voted to close gave this specific reason:

If this question can be reworded to fit the rules in the help center, please edit the question.

Really, it could be useful.. great question! – SS-3.1415926535897932384626433 Mar 31 '12 at 8:07
As is all-too-typical of app recommendation questions, this one is attracting one-line, spammy answers. – Al E. Nov 16 '13 at 13:31

4 Answers 4

Your best bet would be to follow Google Play on Google+. They always post any kind of news, including promotions for apps, music, movies...

share|improve this answer
I think he means discounts for individual apps in not the likes of the 10cent sale. – Richard Borcsik Mar 31 '12 at 10:09
Well i got CameraZOOM for 50 cents and i am glad i did. I am interested in productivity, organization and tool apps. – Boris_yo Mar 31 '12 at 11:35

I use AppSales. It works well for me.

share|improve this answer
I use this too, and I believe it is the most popular application. It even shows a graph with past prices! It works very well. – Cerberus Oct 31 '12 at 23:06

I've never used it, but this app seems to be what you were looking for:

share|improve this answer
Great.......... – SS-3.1415926535897932384626433 Mar 31 '12 at 10:54
Link is now bad. – jeffm Apr 4 '12 at 19:18

You can set up an alert for the Google Play store at It will email or text you new deals come up.

share|improve this answer
Thanks, found it. – Boris_yo Feb 20 '13 at 17:16

Not the answer you're looking for? Browse other questions tagged or ask your own question.