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Zeiss Ikon
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Simple answer: NO.

A Samsung fast charger puts out 2 A at 5 V. Even if your Belkin unit's output rating is at USB voltage, it's got enough current rating to cover the Samsung's needs. If it's at 120 V, it's got roundly twenty times the power required (maybe less than that, since most low voltage power supplies draw more power than they supply).

As a confirmation of this, I routinely charge my Galaxy S4 through a USB cord and 12V USB charger rated at 2.1 A, but not made or sold by Samsung -- which I bought because the USB port in my car didn't supply enough current, even with the Samsung's fast-charging cord, to give a net positive charge rate when running navigation software.

Simple answer: NO.

A Samsung fast charger puts out 2 A at 5 V. Even if your Belkin unit's output rating is at USB voltage, it's got enough current rating to cover the Samsung's needs. If it's at 120 V, it's got roundly twenty times the power required (maybe less than that, since most low voltage power supplies draw more power than they supply).

Simple answer: NO.

A Samsung fast charger puts out 2 A at 5 V. Even if your Belkin unit's output rating is at USB voltage, it's got enough current rating to cover the Samsung's needs. If it's at 120 V, it's got roundly twenty times the power required (maybe less than that, since most low voltage power supplies draw more power than they supply).

As a confirmation of this, I routinely charge my Galaxy S4 through a USB cord and 12V USB charger rated at 2.1 A, but not made or sold by Samsung -- which I bought because the USB port in my car didn't supply enough current, even with the Samsung's fast-charging cord, to give a net positive charge rate when running navigation software.

Source Link
Zeiss Ikon
  • 604
  • 4
  • 14

Simple answer: NO.

A Samsung fast charger puts out 2 A at 5 V. Even if your Belkin unit's output rating is at USB voltage, it's got enough current rating to cover the Samsung's needs. If it's at 120 V, it's got roundly twenty times the power required (maybe less than that, since most low voltage power supplies draw more power than they supply).