6

I had a call from a new number. I went to create a new contact for it but accidentally clicked on the first item in my contact list. Now, it doesn't seem possible to unlink or unjoin them. When I view that contact, I can view the 'Joined Contacts', and it is joined to the Google contact I clicked on, and there is a minus icon but it is greyed out. How can I unjoin or unlink them or move this number to a new contact?

Using Samsung Galaxy S on Froyo.

7

This isn't actually a linked contact unless the contact you added it to is from a social network. That's why the unlinking won't work.

Go to edit the number, select the entire number and copy it, then delete it from the wrong contact, go back, add a new contact, long-press the phone no. field and select paste. Or you can use pen and paper too if you prefer.

1

I was searching this question because I had a linked device contact with a google contact. I don't know how I got it that way. To unlink 1 contact from another open the contact. Choose the menu and choose separate contact. From that screen it isn't obvious but there is a faded button on the right of each of the contacts that are linked. When you press it, the device will prompt "Separate contact" Cancel or OK. For me I have a contact that is Exchange and Google. It was also linked to another Google and a Device contact. I had to separate the device contact (another person) and the Google contact (a different other person).

0

To unlink 1 contact from another open the contact. Choose the menu and choose separate contact. From that screen you will see a ( - ) button on the right of each of the contacts that are linked. When you press it, the device will prompt "Separate contact" tap ( OK ). Do this to each of the contacts you want to unlink, the last one will stay because its the one that the link was created with.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.