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I want to perform a test: if a certain variable exists, is non-empty, and its value matches an existing directory, then "exists" should be outputted.

I did the following:

$ echo $var

$ if [ -d $var ]; then echo "exists"; fi
exists

I got "exist", although I did not assign any value to $var. Why did this happen, and how do I test this properly?

screenshot

  • If @WillW answered your question, please mark it as accepted! :) – Swivel Jun 4 '19 at 14:42
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I think you need to wrap $var in quotes.

if [ -d "$var" ]; then echo "exists"; fi

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[ -d FILE ] True if FILE exists and is a directory

You probably want to use one of these tests instead:

[ -z STRING ] True of the length if "STRING" is zero.

[ -n STRING ] or [ STRING ] True if the length of "STRING" is non-zero.

From https://www.tldp.org/LDP/abs/html/fto.html

how do I test this properly? if a certain variable exists, is non-empty

This question is discussed in detail https://stackoverflow.com/questions/3601515/how-to-check-if-a-variable-is-set-in-bash here.

its value matches an existing directory

This code [[ "${F1AR[@]}" =~ "${NAME##*/}" ]] checks if values match existing directories. From https://github.com/BuildAPKs/buildAPKs/blob/master/scripts/bash/build/build.github.bash#L59

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