# What is the length and breadth of ONLY the screen in the Nexus 7?

I'm not asking the diagonal values, but the length and breadth ones of the Nexus 7. And only of the LCD screen, not the entire hardware.

The screen size is 151mm * 94mm

You can always use some mathematics to obtain screen size:

``````X = sqrt ( Z^2 / (1 + (VR/HR)^2) )
``````

where:

sqrt = Square Root √‾‾‾

X = screen width

Z = diagonal screen size (7" for Nexus 7)

VR = vertical resolution

HR = horizontal resolution

which for Nexus 7, we have:

``````Z = 7"
VR = 1280
HR = 800
``````

so:

X = sqrt ( 49 / 3.56)

X = 3.71 inches ~ 94mm

Y = (1280/800) * X = 1.6X

Y = 5.936 inches ~ 151mm

so we have 151mm x 94mm which Peanut has linked to.

• This assumes square pixels, which isn't always the case (though it is on the Nexus 7). You want to use the aspect ratio instead. – derobert Nov 30 '12 at 11:12
• does this work for alternative pixel arrangements, like PenTile? – Lie Ryan Dec 2 '12 at 18:36
• @derobert Thanks for the point, OK, so we can simply replace VR/HR with aspect ratio. – yrajabi Dec 5 '12 at 7:21
• @LieRyan Yes, in the cases where pixels are not square, we can use aspect ratio (e.g 4:3 or 16:9) instead of actual resolution values (e.g 1280x800). – yrajabi Dec 5 '12 at 7:24

So you want to know the display area ..

(A.) The non-masked (clear) area of the front face:

A simple metric ruler, and ASUS Nexus 7, gives you ..

OR

(B.) The area of active pixels, on the IPS LCD display:

display pitch: 216 dpi (pixels per inch, leading edge to leading edge)

pixel size: 96% of pitch (guesstimate, without engineering drawings)

pixel geometry: square (identical height, width)

display size (in pixels): 1280 x 800

screen area: (mathematical)

`````` => (height - 1) x pitch + pixel_width by (width - 1) x pitch + pixel_width
=> (1279 x 0.1175 + 0.1128) by (799 x 0.1175 + 0.1128)
=> 150.40 by 94.00 mm
``````

``````  => square root ( height squared + width squared )